What number must be added to each of the numbers 5,7,9,12 to get the number which are in proportion
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(5+x),(7+x),(9+x),(12+x)
(7+x)+(9+x)=(5+x) (12+x)
63+9x+7x+x2
63+16x+x2=60+17x+x2
63+16x=60+17x
63-60=17x-16
X=3 ans
In fifth line the x2and x2 will be cut because when it will be giving there so it will be subtracted
And it is x square
(7+x)+(9+x)=(5+x) (12+x)
63+9x+7x+x2
63+16x+x2=60+17x+x2
63+16x=60+17x
63-60=17x-16
X=3 ans
In fifth line the x2and x2 will be cut because when it will be giving there so it will be subtracted
And it is x square
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