Question

what number must be added to each of the numbers 6,10,8,13 to get the numbers which are in proportion ​

Answer 1

Answer:

2 must be added to each of the number 6, 10, 8, and 13 to get the numbers in proportion.

Step-by-step explanation:

Let the number to be added be x.

Now, according to the Question,

(6 + x)/(10 + x) = (8 + x)/(13 + x)

Cross multiplying we get,

(6 + x)(13 + x) = (10 + x)(8 + x)

78 + 6x + 13x + x² = 80 + 10x + 8x + x²

x² - x² + 19x + 78 = 18x + 80

19x + 78 = 18x + 80

19x - 18x = 80 - 78

x = 2

Hence,

2 must be added to each of the number 6, 10, 8, and 13 to get the numbers in proportion.

Let's check it,

(6 + 2)/(10 + 2) = (8 + 2)/(13 + 2)

8/12 = 10/15

4/6 = 2/3

2/3 = 2/3

Thus, its correct.

Hope it helped and believing you understood it........All the best

Answer 2

Answer:

when we add 6240 in the above numbers then we get this numbers in proportion

for solving this question , HCF of this all numbers is

= 6240

:-so, when we add 6240 in above numbers then we get this numbers in proportion