Question

What number must be added to each of the numbers 7, 16, 43 and 79, so that the
new numbers are in proportion?​

Answer 1

Answer:

we have to add 5

Step-by-step explanation:

if we add to them the nos are

12 , 21, 48, 84.

12×84 =1008

21×48=1008

Answer 2

The number must be added to each of the numbers 7, 16, 43 and 79, so that the  new numbers are in proportion is 5.

Step-by-step explanation:

To find : What number must be added to each of the numbers 7, 16, 43 and 79, so that the  new numbers are in proportion?​

Solution :

Let the number be 'x'.

Then the new numbers are 7+x,16+x,43+x,79+x.

The  new numbers are in proportion then

$\frac{7+x}{16+x}=\frac{43+x}{79+x}$

Cross multiply,

$(7+x)(79+x)=(43+x)(16+x)$

Solve,

$553+7x+79x+x^2=688+43x+16x+x^2$

$553+86x=688+59x$

$86x-59x=688-553$

$27x=135$

$x=\frac{135}{27}$

$x=5$

Therefore, the number must be added to each of the numbers 7, 16, 43 and 79, so that the  new numbers are in proportion is 5.

#Learn more

Find the number that must be subtracted from each term of the ratio 27 : 43 to make it  7:15

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