Question

What number must be added to each term of ratio 9:16 make the ratio 2:3​

Answer 1

AnswEr:-

Your Answer Is 5.

ExplanaTion:-

Given:-

• A ratio = 9:16.

To Find:-

• The number which should be added to the given ratio to make it 2:3.

So Now,

Let that Number be x.

In question it is said that if we add x to both the terms the ratio should become 2 : 3.

$\tt\mapsto9 + x \ratio 16 + x = 2 \ratio3.$

$\tt\mapsto \dfrac{9 + x}{16 + x} = \dfrac{2}{3}.$

$\tt\mapsto3(9 + x) = 2(16 + x)\: \: \: \: \rm(cross \: multiplication).$

$\tt\mapsto27 + 3x = 32 + 2x.$

$\tt\mapsto3x - 2x = 32 - 27.$

$\bf\large\mapsto \boxed{ \bf x = 5.}$

Therefore 5 should be added to each term of 9:16 to make it 2:3.

VerificaTion:-

$\tt\mapsto9 + 5 \ratio16 + 5$

$\tt = \cancel{14} \ratio \cancel{21}.$

$\large\boxed{ \bf = 2 \ratio3}.$

...Hence verified...

Answer 2

Answer:5

Step-by-step explanation:

9:16 also writen as 9/16 as   and 2:3 as2/3 then

Let x be the required number.

Then, (9 + x) : (16 + x) = 2 : 3

solution

9+x

16+x

 =  

2 Let x be the required number.

Then, (9 + x) : (16 + x) = 2 : 3

⇒

9+x

16+x

 

=  

2

3

 

⇒27 + 3x = 32 + 2x⇒x =5

Hence, 5 must be added to each term of the ratio 9 : 16 to make it 2 : 3.

3

⇒27 + 3x = 32 + 2x⇒x =5

Hence, 5 must be added to each term of the ratio 9 : 16 to make it 2 : 3.