Question

what number must be added to each term of rhe ratio 9:16to make the ratio 2:3

Answer 1

first we can take 9:6 and 2:3 as (9+x):(16+x)=2:3
=9+×/16+x × 2/3
2(16+x)=3(9+x)
32+3x=27+2x
we have to find 2:3 so we can add both the x numbers:-
I.e. x=5 ans

Answer 2

first we can take 9:6 and 2:3 as (9+x):(16+x)=2:3

=9+×/16+x × 2/3

2(16+x)=3(9+x)

32+3x=27+2x

we have to find 2:3 so we can add both the x numbers:-

I.e. x=5 ans

Hope this help you..