Math, asked by amjadhav1047, 11 months ago

what number must be added to each term of the ratio 8 :11 to make it 4 :5

Answers

Answered by mustafamirza2006
2

Answer:

8+x/11+x = 4/5

BY CROSS MULTIPLICATION

5(8+x)=4(11+x)

40+5x=44+4x

5x-4x=44-40

x=4

HENCE THE NUMBER TO BE ADDED IS 4

HOPE IT HELPS

PLZ MARK IT AS THE BRAINLIEST ANS

Answered by sushilasushila123
0

Answer:

2

Step-by-step explanation:

8:11::4:5

Let x must be needed

8+x:11+x::4+x:5+x

8+x/11+x=4+x/11+x

(8+x)(5+x)=(4+x)(11+x)

x^2+13x-40=x^2+15x+44

x^2+13x-x^2-15x=44-40

-2x=4

x=2

Similar questions