what number must be added to each term of the ratio 8 :11 to make it 4 :5
Answers
Answered by
2
Answer:
8+x/11+x = 4/5
BY CROSS MULTIPLICATION
5(8+x)=4(11+x)
40+5x=44+4x
5x-4x=44-40
x=4
HENCE THE NUMBER TO BE ADDED IS 4
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Answered by
0
Answer:
2
Step-by-step explanation:
8:11::4:5
Let x must be needed
8+x:11+x::4+x:5+x
8+x/11+x=4+x/11+x
(8+x)(5+x)=(4+x)(11+x)
x^2+13x-40=x^2+15x+44
x^2+13x-x^2-15x=44-40
-2x=4
x=2
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