Question

What number must be added to each term to the ratio 5:7 to make the ratio 3:4?

Answer 1

Answer:

Let the two numbers are x and y, then

xy=57⟹x=5y7

Also

x+5y+5=34⟹5y7+5y+5=34⟹5y+357y+5=34

⟹5y+357(y+5)=34⟹4(5y+35)=21(y+5)⟹y=35

⟹x=35×57=25

Let us check

xy=2535=57

x+5y+5=25+535+5=3040=34

Answer 2

Answer:

here is your answer

Step-by-step explanation:

Given ratio is 5:37

Let the number which is to be added to each term of given ratio be a

Now the given ratio becomes (5+a):(37+a) , Given that it is equal to 1:3

⇒

37+a

5+a

=

3

1

⇒15+3a=37+a

⇒2a=22

⇒a=11

Therefore number 11 should be added to each term of the ratio 5:37 to make it equal to 1:3