what number must be added to the each term of the ratio 7 is to 5 so that the ratio becomes 5 to 4
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(7+x):(5+x)=5:4
=7+x/5+x=5:4
=4(7+x)=5(5+x)
=28+4x=25+5x
=28+23=9x
=51=9x
=x=51÷9
=x=5⅔
=7+x/5+x=5:4
=4(7+x)=5(5+x)
=28+4x=25+5x
=28+23=9x
=51=9x
=x=51÷9
=x=5⅔
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