Math, asked by fbareena, 2 days ago

what number must be subtracted from each of numbers 31 ,19,13 and 10 so that they are in proportion

Answers

Answered by dkchakrabarty01

3

Answer:

Let the number be n. Then it is given

(31-n)(10-n)=(19-n)(13-n)

n^2-41n+310=n^2-32n+19×13

-9n=-310+247=-63

n=63/9=7 Ans

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