Question

What number must be subtracted from each of the number 23 , 40 , 57 and 108 to get the number which are in proportion​

Answer 1

Answer:

Let the no. To be subtracted be x . Then ,

(23-x):(40-x)::(57-x):(108-x)

=(23-x)/(40-x)=(57-x)/(108-x)

=(23-x)(108-x)=(40-x)(57-x)

=2484-131x+2x=2280-97+2x

=34x=204 =

x = 204/34=6

hope it helps

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