Question

What number must be subtracted from each of the number 31,26 and 22. So that the remainder may be in proportion

Answer 1

Answer:

2

Step-by-step explanation:

Let x be  the number which has too be subtracted

Then

14-x / 17-x = 34-x / 42-x

(14-x)(42-x) = (34-y)(17-x)

x^2-56x+558 = x^2-51x+578

5x = 10

x = 2

Answer 2

Answer:

Let the required number be x.

According to given, 31 - x, 26 - x and 22 - x are in continued proportion.

(31 - x) / (26 - x) = (26 - x) / (22 - x)

(26 - x)² = (31 - x) (22 - x)

676 - 52x + x² = 682 - 53x + x²

676 - 52x = 682 - 53x

53x - 52x = 682 - 676

x = 6

Hence, the required number is 6