What number must be subtracted from each of the numbers 23,16,20 and 14 so that the resulting numbers are in proportion?
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let number be x
[tex] \frac{23-x}{16-x} = \frac{20-x}{14-x} \\ (23-x)(14-x) = (20-x)(16-x) \\ 37x + 23(14) = 36x + 20(16) \\ x = 20(16) - 23(14) = -2 [/tex]
So 2 must be subtracted to bring numbers in proportion
21:14::18:12
[tex] \frac{23-x}{16-x} = \frac{20-x}{14-x} \\ (23-x)(14-x) = (20-x)(16-x) \\ 37x + 23(14) = 36x + 20(16) \\ x = 20(16) - 23(14) = -2 [/tex]
So 2 must be subtracted to bring numbers in proportion
21:14::18:12
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