Math, asked by LUICIFER666007, 1 year ago

what number must be subtracted from each of the numbers 41 ,55, 36, 48 so that difference are in proportion

Answers

Answered by Raghul101
110
Answer:6
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Answered by KailashHarjo
13

Answer:

Answer:

First of all, let us assume the number which should be substracted is X.

now, X must satisfy the condition (41-X):(51-X)::(36-X):(48-X)

now by cross multiplying, we get,   (41-X)x(48-X)=(36-X)x(51-X)

now if you will solve further you will get answer is 6

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