what number must be subtracted from each of the numbers 41 ,55, 36, 48 so that difference are in proportion
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Answered by
110
Answer:6
Please refer the above image for the solution.
Hope its useful.
Please refer the above image for the solution.
Hope its useful.
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Answered by
13
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Answer:
First of all, let us assume the number which should be substracted is X.
now, X must satisfy the condition (41-X):(51-X)::(36-X):(48-X)
now by cross multiplying, we get, (41-X)x(48-X)=(36-X)x(51-X)
now if you will solve further you will get answer is 6
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