Question

what number must be subtracted from each of the numbers 41, 55, 36, 48 so that the differeces are proportional?

Answer 1

a/b= c/d
let the number be X, so the equation will be
a-x/b-x= c-x/ d-x
thus
41-x/55-x= 36-x/48-x
(41-x) (48-x) = (36-x) (55-x)
1968- 41x- 48x+ x²= 1980- 36x- 55x+ x²
1968- 89x = 1980-91x
-89x + 91x = 1980-1968
2x = 12
x= 6
41-6/55-6= 36-6/48-6
35/49=30/42

Answer 2

Answer:

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