Question

What number must be subtracted from each of the numbers 9,16, and 30, so that they are in continued proportion?

Answer 1

Solution :-

Let x is be subtracted from each of the numbers 9,16, and 30, so that they are in continued proportion .

so,

→ (9 - x) * (30 - x) = (16 - x)²

→ 270 - 9x - 30x + x² = 256 + x² - 32x

→ 270 - 39x = 256 - 32x

→ 270 - 256 = 39x - 32x

→ 7x = 14

→ x = 2 (Ans.)

Therefore, 2 is subtracted from each of the numbers 9,16, and 30, so that they are in continued proportion .

Learn more :-

let a and b positive integers such that 90 less than a+b less than 99 and 0.9 less than a/b less than 0.91. Find ab/46

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