Question

what number must be subtracted from each term of the ratio 17:13so that the ratio becomes 7:15?​

Answer 1

Answer:

What number must be subtracted from each term of ratio 17:33

Let the rational between the term of ratio be x.

Thus the numbers are 17x and 33x

Let the number n to be subtracted from both the number of ratio.

After subtracting n the numbers will be 17x - n and 33x - n and their ratio 7: 15. Accordingly

17x - n / 33x - n = 7/15

Cross multiplication

15 (17x - n) = 7 ( 33x - n)

255x - 15n = 231x - 7n

255x - 231x = 15n - 7n

24x = 8n

n= 24x/8

n = 3x

Thus 3x to be subtracted from each number.

Answer the value 3x to be subtracted from each number, in which x can be any integer.

On subtracting 3x the number will be 17x - 3x = 14x and 33x - 3x = 30x

Their ratio 14x/30x = 14/30 or 7/15

Step-by-step explanation:

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