Question

What number must be subtracted from each term of the ratio 17 : 33 so that the ratio
becomes 7 : 15?
pls show proper step by step explanation ​

Answer 1

Original ratio = 17 : 33

New ratio = 7 : 15

Let the number to be subtracted = a

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According to the question:

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$\rm\longrightarrow \dfrac{17-a}{33-a} = \dfrac{7}{15}$

$\rm\longrightarrow 15(17-a)=7(33-a)$

$\rm\longrightarrow 255-15a = 231-7a$

$\rm\longrightarrow 255-231=15a-7a$

$\rm\longrightarrow 24=8a$

$\rm\longrightarrow \dfrac{24}{8}=a$

$\rm\longrightarrow 3 = a$

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3 be subtracted from each term of the ratio 17 : 33 to get the ratio 7 : 15.

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More:

Ratio refers to the relation between two quantities. We use ratio to compare two or more quantities.

Convert ratio into fractions:

Add up the quantities and use the sum as denominator.

ex: 4 and 2, 4 + 2 = 6

Now, show the numbers as a fraction of the sum: 4/6 = 2/3 and 2/6 = 1/3

Answer 2

Question ::-

What number must be subtracted from each term of the ratio 17 : 33 so that the ratio becomes 7:15?

Given ::-

• given ratio = 17:13

• After , subtracting a no. ratio becomes = 7:15

To find ::-

• Find the number ?

Solution ::-

Let the number be x

A.T.Q ::-

$➠ \: \: \: \: \: \dfrac{17 - x}{33 - x} = \dfrac{7}{15}$

$➠ \: \: \: \: \: 15(17 - x)= 7(33 - x)$

$➠ \: \: \: \: \: 255 - 15x=231 - 7x$

$➠ \: \: \: \: 255 - 231 = 15x - 7x$

$➠ \: \: \: \: 24 = 8x$

$➠ \: \: \: \: \dfrac{24}{8} = x$

$➠ \: \: \: \: 3 = x$

Hence , number is 3

3 will be subtracted from 17:13 to form 7:15

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