Question

what number must be subtracted from each term of the ratio 17-33 so that the ratio becomes 7 ratio 15

Answer 1

$\textbf{\huge{ANSWER:}}$

Let the number be = x

Therefore:

$\frac{17 - x}{33 - x} = \frac{7}{15} \\ \\ = > 15(17 - x) = 7(33 - x) \\ \\ = > 225 - 15x = 231 - 7x \\ \\ = > 225 - 231 = 15x - 7x \\ \\ = > 24 = 8x \\ \\ = > x = \frac{24}{8} \\ \\ = > x = 3$
Hope it Helps!! :)

Answer 2

$\mathsf{Here's \: \: the \: \: answer}$

Let the given number be assumed as x

Therefore,

According to the given condition,

$\tt{ \frac{17 - x}{33 - x} = \frac{7}{15}}$

$\tt {\therefore 15(17 - x) = 7(33 - x)}$

$\tt{255 - 15x = 231 - 7x}$

$\tt{255 - 231 = - 7x + 15x}$

$\tt{24 = 8x}$

$\tt {x = 3}$

Thus,

The number 3 should be subtracted.

Thanks!!