what number must be subtracted from the each term of the ratio 17:33 so that the ratio becomes 7:15??
Answers
Answered by
3
let , the no. be x
a/q, 17/33 - x = 7/15
-x = 7/15 - 17/33
= -8/165
x = 8/165
=8:165
a/q, 17/33 - x = 7/15
-x = 7/15 - 17/33
= -8/165
x = 8/165
=8:165
perminderKaur:
incorrect
Answered by
20
Step-by-step explanation:
Define x:
Let x be the number to be subtracted
Original ratio = 17 : 33
New ratio = 7 : 15
Form equation:
(17 - x)/(33 - x) = 7/15
Solve x:
(17 - x)/(33 - x) = 7/15
Cross multiply:
15(17 - x) = 7(33 - x)
Distribute 15 and 7:
255 -15x = 231 -7x
Add 15x to both sides:
255 = 231 + 8x
Subtract 231 from both sides:
24 = 8x
Switch sides:
8x = 24
Divide by 8:
x = 3
hope this answer helpful u
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