Math, asked by perminderKaur, 1 year ago

what number must be subtracted from the each term of the ratio 17:33 so that the ratio becomes 7:15??

Answers

Answered by skraj4583
3
let , the no. be x
a/q, 17/33 - x = 7/15

-x = 7/15 - 17/33
= -8/165

x = 8/165
=8:165

perminderKaur: incorrect
Answered by Anonymous
20

Step-by-step explanation:

Define x:

Let x be the number to be subtracted

Original ratio = 17 : 33

New ratio = 7 : 15

Form equation:

(17 - x)/(33 - x) = 7/15

Solve x:

(17 - x)/(33 - x) = 7/15

Cross multiply:

15(17 - x) = 7(33 - x)

Distribute 15 and 7:

255 -15x = 231 -7x

Add 15x to both sides:

255 = 231 + 8x

Subtract 231 from both sides:

24 = 8x

Switch sides:

8x = 24

Divide by 8:

x = 3

hope this answer helpful u


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