Question

what number must ve subtracted from each of the number 41,55,36,48 , so that the difference are proportional ​

Answer 1

Let the no. to be subtracted be x

Then, According to the QUESTION

$(41 - x) : (55 - x) : : (36 - x) :(48 - x)$

$= > \frac{41 - x}{55 - x} = \frac{36 - x}{48 - x}$

$= > (41 - x)(48 - x) = (36 - x)(55 - x)$

$=> 1968 - 41x - 48x + {x}^{2} = 1980 - 36x - 55x + {x}^{2}$

$= > 91x - 89x = 1980 - 1968$

$= > 2x = 12$

$= > x = 6$