Question

what number of electron are present in 18ml of water ?​

Answer 1

Hii its tom85

1 ml = 1/1000L

18ml = 18/1000L

molecular mass of water = 18

no of mole (n) = 18/18000 = 10^-3

so number of electron present = 6.022*10^23 *10^-3= 6.022 * 10^20

where 6.022*10^23 = avagerdo cinstant

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