Question

What number of moles of Fe(OH) 3 that can be produced by allowing 1mole of FeS3 2 moles ofH2O and 3moles of O2 to react?

Answer 1

Here 1 mole Fe2S3 , 2 mole H2O , 3 mole O2 is given.

But in the given reaction the reactants are in the ratio 2:6:3 or 1:3:1.5. but given ratio of reactants is 1:2:3.

So, it can be clearly seen that H2O is the limiting reagent as 1 mole of Fe2S3 would require 3 mole of H2O which is not available.

So, the reaction will take place according to the amount of H2O.

Now 6 mole H2O produces 4 mole of Fe(OH)3.

Thus 2 mole H2O will produce = (4/6)*2 mole = 4/3 mole of Fe(OH)3 _____(Ans.)

Hope it helps....

Answer 2

Explanation:

ignore handwriting

H20 is the limiting reagent since 6 mole of H20 produce 2 mole of Fe2S3