what number should be added to -5/6 so get _3/2
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Answered by
0
Answer:
Let the required number be x.
x+(-5/6)=3/2
x=3/2+5/6
x=(9+5)/6
x=14/6
x=7/3.
Therefore the required number=7/3.
Answered by
0
Answer:
If its 3/2 in the question:
Solve for x:
x - 5/6 = 3/2
Put each term in x - 5/6 over the common denominator 6: x - 5/6 = (6 x)/6 - 5/6:
(6 x)/6 - 5/6 = 3/2
(6 x)/6 - 5/6 = (6 x - 5)/6:
(6 x - 5)/6 = 3/2
Multiply both sides of (6 x - 5)/6 = 3/2 by 6:
(6 (6 x - 5))/6 = 6×3/2
6×3/2 = (6×3)/2:
(6 (6 x - 5))/6 = (6×3)/2
(6 (6 x - 5))/6 = 6/6×(6 x - 5) = 6 x - 5:
6 x - 5 = (6×3)/2
6/2 = (2×3)/2 = 3:
6 x - 5 = 3×3
3×3 = 9:
6 x - 5 = 9
Add 5 to both sides:
6 x + (5 - 5) = 5 + 9
5 - 5 = 0:
6 x = 9 + 5
9 + 5 = 14:
6 x = 14
Divide both sides of 6 x = 14 by 6:
(6 x)/6 = 14/6
6/6 = 1:
x = 14/6
The gcd of 14 and 6 is 2, so 14/6 = (2×7)/(2×3) = 2/2×7/3 = 7/3:
Answer: |
| x = 7/3
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