Question

What number should be added to 6 /11 to get 29 /33 ?

Answer 1

Hope this helps you mate this is written by me.

Answer 2

The number that should be added to $\frac{6}{11}$ to get $\frac{29}{33}$ is $\frac{1}{3}$

• The given numbers are known as fractions as they consist of a numerator and a denominator.
• Fractions are numbers that represent a portion of a whole number which means that it is said to be the part of a whole and hence the name fraction.
• Fractions are numbers that are not divided completely. This means that when divided they do not give a whole number as a result and instead leave some remainder behind.
• This means that on dividing the numbers some remainder is obtained and the remainder is not zero. Thus numbers which are not divisible with each other form fractions.
• The given fractions are said to be proper fractions as the numerator value is lesser than the denominator value.
• It is given that a number must be added to the fraction $\frac{6}{11}$ to get the result as $\frac{29}{33}$. Let this unknown number be x where x is also a fraction.
• Thus, we can construct a mathematical equation to represent the same:

                                                          $\frac{6}{11} +x=\frac{29}{33}$

• From the concept of algebraic equations we know that when a term shifts from one side of the equation to the other it changes its sign.
• Here, we make x is the unknown fraction and hence we need to make it as the subject and shift the term $\frac{6}{11}$ to the other side.
• There are three terms in the equation and all of them are positive and thus when is $\frac{6}{11}$ shifted to the other side of the equation its sign is reversed to be negative.
• Hence, we have:
• $x=\frac{29}{33}-\frac{6}{11}$
• By using the concept of addition or subtraction of fractions we know that in-order to carry out the subtraction operation the denominators must be the same.
• If the denominators are not equal we take the LCM to bring it to the same number.
• Here, the term $\frac{6}{11}$ is multiplied by 3 on both the numerator and denominator as 11 is divisible by 33 in-order to make the denominators the same.

• Thus, we have:

                                                        $\implies x=\frac{29}{33}-\frac{18}{33}$

                                                        $\implies x=\frac{29-18}{33}$

                                                        $\implies x=\frac{11}{33}$

• This is the value of x. But the fraction is not in its simplified form yet and thus by simplifying further we have:

                                                       $x=\frac{1}{3}$

This is the number which when added to $\frac{6}{11}$ would give $\frac{29}{33}$.

https://brainly.in/question/18683245

https://brainly.in/question/31601783

#SPJ3