Question

What number should be added to 6, 15, 20 and 43 to make the numbers proportional?

Answer 1

Answer:

Step-by-step explanation:

Let no. be ‘x’

∴  6 + x/15 + x = 20 + x/43 + x

⇒ (6 + x)(43 + x) = (20 + x)(15 + x)

⇒ 258 + 49x + x2 = 300 + 35x + x2

⇒ 14x = 42

x = 3

∴  The required no is 3.

Answer 2

Answer:

3

Step-by-step explaination

6+k/15+k =20+k/43+k

(6+k)(43+k)=(20+k)(15+k)

(258+6k+43k+k²)=300+20k+15k+k²

258+49k=300+35k

14k=42

k=3

Therefore, 3 must be added to 6, 5, 20 and 43 to make the numbers proportional

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