what number should be added to each of the number 12, 22, 42 and 72 so that the resulting number may be in proportion
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Let x be the number to be added
(12+x):(22+x): :(42+x):(72+x)
(12+x)/(22+x)=(42+x)/(72+x)
(12+x)(72+x)=(42+x)(22+x)
864+12x+72x+x^2=924+42x+22x+x^2
84x-64x=924-864
20x=60
x=3
Therefore 3 should be added to 12,22,42 and 72 so that the resulting number may be in proportion.
Hope its useful.
(12+x):(22+x): :(42+x):(72+x)
(12+x)/(22+x)=(42+x)/(72+x)
(12+x)(72+x)=(42+x)(22+x)
864+12x+72x+x^2=924+42x+22x+x^2
84x-64x=924-864
20x=60
x=3
Therefore 3 should be added to 12,22,42 and 72 so that the resulting number may be in proportion.
Hope its useful.
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