Question

What number should be added to make quadratic equation x^2-6x =16 a perfect square?

Answer 1

add (+9) on both side

Answer 2

Answer:

Step-by-step explanation

it  is simple

equation is x^2-6x-16=0------given

first change -16 into 16 because square is never -ve

so add  32

now equation =x^2-6x+16=0----1

according to identity [x]^2 -8x+16=[x-4]^2  now this a perfect square

so add -2x for ----- 1

so we need to add 32-2x

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or  just add 9 on both side

X^2 -6x +9=16+9

[x-3]^2=5^2

hope it helps

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