what number should be multiplied with 35/42 so that the square root of the product will give 2
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Answered by
11
Answer :
Let us consider that the required number is x
Then,
35/42 × x = 35x/42
By the given condition,
√(35x/42) = 2
⇒ 35x/42 = 4,
squaring both sides
⇒ x = (4 × 42)/35
⇒ x = (4 × 6)/5
⇒ x = 24/5
Therefore, the required number is 24/5.
#MarkAsBrainliest
Let us consider that the required number is x
Then,
35/42 × x = 35x/42
By the given condition,
√(35x/42) = 2
⇒ 35x/42 = 4,
squaring both sides
⇒ x = (4 × 42)/35
⇒ x = (4 × 6)/5
⇒ x = 24/5
Therefore, the required number is 24/5.
#MarkAsBrainliest
Answered by
9
Hi there!
Let that number be = n
Then,
35 / 45 × n = 35n / 45 = 5n / 6
ATQ,
√5n / 6 = 2
Squaring both sides of the eqn.
5n / 6 = 2²
5n / 6 = 4
n = 4 × 6 / 5
n = 24 / 5
Hence,
The required no. = n = 24 / 5 should be multiplied to get product as 2
Hope it helps! :)
Let that number be = n
Then,
35 / 45 × n = 35n / 45 = 5n / 6
ATQ,
√5n / 6 = 2
Squaring both sides of the eqn.
5n / 6 = 2²
5n / 6 = 4
n = 4 × 6 / 5
n = 24 / 5
Hence,
The required no. = n = 24 / 5 should be multiplied to get product as 2
Hope it helps! :)
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