Question

What number should be subtracted from -2/3 to get -1/6 ?​

Answer 1

Answer:

-3/6

Step-by-step explanation:

Let the number be 'x'.

-2/3 -x= -1/6

-2/3 = -1/6+x

-2/3+ 1/6( LCM of 3 and6 = 6) = x

-2*2/3*2+1/6=x

-4/6+1/6=x

-3/6=x

Answer 2

Answer:

• The required number is -1/2.

Step-by-step explanation:

To Find:

• What number should be subtracted from -2/3 to get -1/6 ?

Let us assume:

• Let the number to be subtracted be x.

Then,

According to the question,

$\rm{\longmapsto\dfrac{-2}{3}-x=\dfrac{-1}{6}}$

Transposing variables and constants on different sides,

$\rm{\longmapsto\dfrac{-2}{3}+\dfrac{1}{6}=x}$

Adding the numbers,

$\rm{\longmapsto\dfrac{(-2\times2)+(1\times1)}{6}=x}$

$\rm{\longmapsto\dfrac{-4+1}{6}=x}$

$\rm{\longmapsto\dfrac{-3}{6}=x}$

Reducing the numbers,

$\rm{\longmapsto\dfrac{-3\div3}{6\div3}=x}$

$\rm{\longmapsto\dfrac{-1}{2}=x}$

Hence, -1/2 should be subtracted from -2/3 to get -1/6 as result.

Verification:

LHS:

$\sf\hookrightarrow\dfrac{-2}{3}-\bigg(\dfrac{-1}{2}\bigg)$

$\sf\hookrightarrow\dfrac{-2}{3}+\dfrac{1}{2}$

$\sf\hookrightarrow\dfrac{-4+3}{6}$

$\sf\hookrightarrow\dfrac{-1}{6}$

RHS:

$\sf\hookrightarrow\dfrac{-1}{6}$

As,

• LHS = RHS

Hence, verified.