Question

what number should be subtracted from each of 50,61,92,117so that the numbers so obtained in this order are in proportion ​

Answer 1

Step-by-step explanation:

Let the number be x

a/q

50-x/61-x=92-x/117-x

(50-x)(117-x)=(92-x)(61-x)

5850-50x-117x-x^2=5612-92x-61x-x^2

5850-5612=167x-153x

238=14x

x=17

hence 33:44::65: 100