Question

what number should be subtracted from each of the
umbers 4,10 and 28 so that the remainder may be in
continued proportion?
(Ans:1)
​

Answer 1

Answer:

1

Step-by-step explanation:

If a, b and c are in continued proportion, a:b=b:c

So, a×c=b×b

Let the number be x.

So, by given conditions:

$(4 - x)(28 - x) = {(10 - x)}^{2} \\ 112 - 32x + {x}^{2} = {x}^{2} - 20x + 100 \\112 - 32x = 100 - 20x \\ 12 = 12x \\ x = 1$

Hence, when 1 is subtracted from 4, 10 and 28 each, the resultant numbers are in numbers are in continued proportion.