what number should be subtracted from x^2 + 8 x + 20 get (X + 4)^2
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Question :----
- we have to find what number whould be subtracted from x² + 8x +20 to get (x+4)² ?
Formula used :----
- (a+b)² = a² + b² + 2ab
Solution :-----
First lets solve (x+4)² by above formula , we get,
(x+4)² = x² + 16 + 8x
Now,
To Find the required number ,
subtraction x² + 16 + 8x from x² + 8 x + 20 ..
so, we get,
(x² + 8x +20) - (x² + 8x +16)
→ x² + 8x + 20 - x² - 8x -16
→ x² - x² + 8x - 8x + 20 - 16
→ 20 - 16
→ 4 (Ans)
Hence, if we subtract 4 from x² + 8 x + 20 we will get , (x+4)² ....
(Hope it helps you)
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