What number whose sum of its digits 26 become 6 000 when rounded to the nearest thousands list 3 possible answer
Answers
Answer:
6497 , 5579 , 5993
Explanation:
There are several such numbers. Since the number rounds to 6,000 , it must be greater than 5,500 and less than 6,500 . Therefore the first digit must be 5 or 6 . Suppose it’s 5 . Then the remaining three digits must add to 21 and at least one of the digits (the one in second position) must be 5 or more. Suppose the second digit is 5. Then the last two digits must add up to 16, which means that they are 7+9, 8+8, or 9+7, corresponding to 5,579, 5,588, and 5,597. We can proceed like this systematically to come up with all the possibilities with 5 as the first digit:
5,579, 5,588, 5,597, 5,669, 5,678, 5,687, 5,696,5,759, 5,768, 5,777, 5,786, 5,795, 5,849, 5,858,5,867, 5,876, 5,885, 5,894, 5,939, 5,948, 5,957,5,966, 5,975, 5,984, 5,993
Similarly, when the first digit is 6 , the remaining three digits must add up to 20 and the digit in the second position must be less than 5. Again, we can come up with a few possibilities (although not quite as many):
6,299, 6,389, 6,398, 6,479, 6,488, 6,497
I believe that’s all of them.