Question

what nust be subtracted from
${x}^{4} + 2 {x}^{2} - 3x + 7 \: to \: get \: {x}^{3} + {x}^{2} + x - 1$
​

Answer 1

Answer:

$- {x}^{4} - {x}^{3} + {x}^{2} + 4x - 8$

Step-by-step explanation:

Let the number be y.

${x}^{4} + 2 {x}^{2} - 3x + 7 - y = {x}^{3} + {x}^{2} + x - 1 \\ = >- y = {x}^{3} + {x}^{2} + x - 1 - ( {x}^{4} + 2 {x}^{3} - 3x + 7) \\ = >- y = {x}^{3} + {x}^{2} + x - 1 - {x}^{4} - 2 {x}^{3} + 3x - 7 \\ = >- y = - {x}^{4} - {x}^{3} + {x}^{2} + 4x - 8\\=> y = x^{4}+ x^{3}-x^{2}-4x+8$

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