Question

what % of am wave power is carried by side bands for m=1

Answer 1

Answer: 33.3% of total power is carried by side band.

Explanation:

Given that,

m = 1

We know that,

$\dfrac{Power\ of\ side\ band}{total\ power}$ = $\dfrac{m^{2}}{2+m^{2}}$

$\dfrac{Power\ of \ side \ band}{total\ power}$ = $\dfrac{1}{3}$

Now, the percentage of AM wave power is

Power carried by side band = $\dfrac{1}{3}$ of total power

Power carried by side band = 33.3% of total power

Hence, 33.3% of total power is carried by side band.