What % of kinetic energy of a moving particle is transferred of a stationary particle when moving particle strikes with stationary particle of mass equal in mass
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1
Answer:
Explanation:
Here, m1=m,u1=υ
, say,m2=4m
u2=0,υ1=?
υ1=(m1−m2)u1+2m2u2m1+m2
υ
1
=
(
m
1
-
m
2
)
u
1
+
2
m
2
u
2
m
1
+
m
2
υ1=(m−4m)υ+0m+4m=−35υ
υ
1
=
(
m
-
4
m
)
υ
+
0
m
+
4
m
=
-
3
5
υ
initial K.E.,E1=12m1u21=12mυ2
K
.
E
.
,
E
1
=
1
2
m
1
u
1
2
=
1
2
m
υ
2
finl K.E.,E2=12m1υ1=(1)2=12m(−35υ)2
K
.
E
.
,
E
2
=
1
2
m
1
υ
1
=
(
1
)
2
=
1
2
m
(
-
3
5
υ
)
2
=12×925mυ2
=
1
2
×
9
25
m
υ
2
%K.E.
%
K
.
E
.
transferred =(E1−E2)E1×100
=
(
E
1
-
E
2
)
E
1
×
100
=(1−925)12mυ2×10012mυ2=64%
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