Question

What os the length of the diagonal of the triangle (hint:by Pythagoras) theorem ​

Answer 1

Answer:

1)

$ad \: = \: \sqrt{{9}^{2} + {12}^{2} } \\ = \sqrt{81 + 144 } \\ = \sqrt{125} \\ = \sqrt{15}$

2) Since, CD = 8cm

Therefore, AB = 8cm

Now,

$bd \: = \: \sqrt{ {6}^{2} + {8}^{2} } \\ = \sqrt{36 + 64} \\ = \sqrt{100} \\ = 10cm$