WhAt os the sum of 10term of an AP 41,36,31,26
Answers
Answered by
1
Soln:-
The sum of 10term,
S10 = 185
Summation of n terms in A. P.
Sn = n/2 [2a+(n-1)d]
41,36,31,26. ..A.P.
a = 41, d = t2-t1 = 36-41 = -5
To find :-
S10 = 10/2 [2a+(10-1)d]
= 5[2(41) + 9(-5)]
= 5(82-45)
= 5(37)
= 185
Answered by
0
Answer:
-590
Step-by-step explanation:
x = 41 d = -5
x₁₀ = dn + (x-d)
= -5 * 41 + (41 - (-5))
= -159
sum = n/2 (x + xₙ)
= 10/2 (41 + (-159))
= - 590
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