Question

What Oxidation state of Xe in Xe O2F4?



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Answer 1

Oxygen is more electronegative than xenon, so its oxidation state is −2.

• Fluorine is the most electronegative of the elements, so its oxidation state is −1.

• The XeOF4 molecule is neutral, so the sum of oxidation states of all elements must be 0.

• Thus, Xe+O+4F = Xe+(−2)+4(−1)=0 and therefore Xe=+2+4=+6.

⇒The oxidation state of xenon is +6.

Answer 2

Answer:

oxygen is more electronegative than xeon so its oxidate states is-2.

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