what part of the total current will flow through a galvanometer of resistance 0.6Ω when a 0.2Ω shunt is connected to it?
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combined resistance: 1/R = 1/0.6 + 1/0.2 = 4/0.6 R = 0.15 ohms
voltage across is same. So current is inversely proportional to resistance.
So 0.15 i /0.6 is the current thru galvanometer. That is 25%
voltage across is same. So current is inversely proportional to resistance.
So 0.15 i /0.6 is the current thru galvanometer. That is 25%
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