what part of wooden block (50cm*30cm*20cm)remains above the surface of water when the wooden block is placed in water ?Out of 20 cm height of it ,,what part of its remains out of water ?(the density of wood is 0.8gm/cm^3 and density of water is 1gm/cm^3)
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Answer:
Volume of part of wooden block immersed in water V
in
=(40×40×5) cm
2
=(40×40×5) ×10
−6
m
3
Density of water σ
w
=10
3
kg/m
3
Weight of wooden block = Weight of water displaced
Mg=V
in
σ
w
g
Mg=(40×40×5)×10
−6
×10
3
g
⇒M=8 kg
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