Question

What percent of a sample of nitrogen must be allowed?

Answer 1

Assuming ideal gas behaviour,

Apply PV= nRT

In this condition, none of the variables are constant. The only constant in both the cases is R.

So, we can write the equation as (PV)/nT = R

Let us denote the variables in the first case with P1,V1,T1,n1 and the variables in the second case with P2,V2,T2,n2.

So from the above realtion, we can write

{(P1V1)/(n1T1)}={(P2V2)/(n2T2)}

P1=3atm, P2=0.78 atm

V1=1.65 litre, V2=1 litreT2=110 degree celcius = 110+273.15 = 383.15 K

Now substitute everything

{(3*1.65)/(n1*493.15)}={(0.78*1)/(n2*383.15)}

4.95/493.15n1 = 0.78/383.15n2

n2/n1 = 0.203

Since it is same gas, the ratio of number of moles is same as the weight of the nitrogen.

m2/m1=0.203

The percentage of gas escaped is

{(m1-m2)/m1}*100

{1-(m2/m1)}*100

(1-.203)*100 = .797*100 = 79.7%

T1=220 degree celcius = 220+273.15 = 493.15K