What percent of Rs. 8 is Rs. 2?
a) 50
b) 25
c) 0.16
d) 4
ii) In A ABC, AB = AC. If ZBAC + ZACB = 130°, ZACB is -
a) 130°
b) 80°
c) 50°
d) 100°
iii/H.C.F of (a?x – x3) and 2x (a2 - ax) is –
a) (a + x)
b) x (a - x)
c) 2a (a - x)
d) (a - x)
iv In a graph, a point is situated 4 units away from the origin on the y-axis. The co-ordinate of the point is -
a) (4,0)
b) (0, 4)
c) (0,0)
d) (4,4)
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Answers
Step-by-step explanation:
What percent of Rs. 8 is Rs. 2? 25%
In A ABC, AB = AC. If ZBAC + ZACB = 130°, ZACB is 50°
H.C.F of (a?x – x3) and 2x (a2 - ax) is – x (a - x)
In a graph, a point is situated 4 units away from the origin on the y-axis. The co-ordinate of the point is - (4,0)
Answer:
i) b) 25
%
ii) c) 50°
Since, AB=AC,
Therefore, as we know, angles opposite to equal sides are equal.
So, ZABC = ZACB.
Also, we know that the sum of all the angles of a triangle = 180°
Also, it is given that ZBAC + ZACB = 130°
So, ZABC + ZBAC + ZACB = 180°
⇒ ZABC = 180° - 130° = 50° = ZACB
iii) b) x(a-x)
a²x - x³ = x(a²-x²) = x(a-x)(a+x)
2x(a²-ax) = 2ax(a-x)
HCF = x(a-x)
iv) b) 0,4
Since, the point lies on y-axis therefore, the y-coordinate cannot be 0 and the x-coordinate should be 0.
So, (x,y) = (0,4)
Hope this helps.....