what percent of the area of scalen triangle will decrease if it's sides are ⅓ rd??
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Step-by-step explanation:
Area of triangle = A = square root of [s(s-a)(s-b)(s-c) where 2s =a+b+c.
Each side is halved,
s’ = s/2
(s’-a’) = (s-a)/2.
s’-b’) = (s-b)/2.
s’-c’) = (s-c)/2.
New areaA’ = square root of [s(s-a)(s-b)(s-c) /16. = A/ 4.
Change in area = 3/4 A= 75% decrease
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percentage of decrease =75%
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