Question

What percentage of Fe3+ is present in Feo.930?​

Answer 1

Answer:

Explanation:

We know that in pure iron oxide(FeO),iron and oxygen are present in the ratio 1: 1

In wustite (Fe0.93O1.00),some of the Fe2+ ions are missing and the number of Fe2+ ions present in 0.93 instead of 1.

From here we find the number of missing Fe2+ ions

⇒1.0−0.93=0.07

Since each Fe2+ ion carries two units of positive charge so the total positiv charge missing

⇒0.07×2=0.14

For maintenance of electrical neutrality this much (ie 0.14) positive charge has to be compensated by the presence of Fe3+ ions.

If one Fe3+ ion replaces one Fe2+ ion then there is an increase of one unit positive charge.So to compensate 0.14 unit positive charge we require 0.14 Fe3+ ions to replace Fe2+ ion.

So,100Fe2+ ions have Fe3+ ions=0.140.93×100=15.05%