Question

What percentage of the gas will be escaped out if open vessel is heated from 300 K to 500 K ?

a) 20%
b)40%
c) 50%
d) 70%

Answer 1

Let volume of flask be = 1L

Applying charles law :-

$\frac{v1}{t1} = \frac{v2}{t2}$

where v1 = 1L, T1 = 300k, T2 = 500k

So, v2 = 500/300 = 1.66L

( gas has expanded )

Volume of gas escaped ( 1.66 - 100 ) = 0.66L

Hence, percentage of gas escaped =

$\frac{0.66}{1.66} \times 100 = 39.75$

That is 40 % approx.

Answer 2

Percentage of the gas will be escaped out 40%.

What is Charles Law in simple terms?

• Charles's law, a statement that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant.

What is Charles Law also known as?

• Charles's law (also known as the law of volumes) is an experimental gas law that describes how gases tend to expand when heated.

According to the question:

Let $V_{1}=V, then V_{2} =?$

            $V_{2} = \frac{V_{1}V_{2} }{T_{1} } \\\\\\V_{2} =_\frac{V*T_{2} }{T_{1} } }\\ \\\\=V*\frac{500}{300} \\\\\\V_{2} =\frac{5V}{3}$

So,volume of air escaped=$(V_{2}-V_{1})$

$=(\frac{5V}{3} -V)\\\\=\frac{5V-3V}{3} \\\\V_{2} =\frac{2V}{3}$

So, percentage of air escaped=$\frac{2V}{3}$×$100$×$\frac{3}{5V}$

=40%

Hence, Approximately 40% of the gas will be released.

Learn more about Charles Law here,

https://brainly.in/question/631064?msp_poc_exp=1

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