what percentage of triangle LMN is shaded
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9
Answer:
37.5%
Step-by-step explanation:
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2
Answer:
Side of Equilateral Triangle, a = 14 cm
Angle of sector,
\theta = 60 \degreeθ=60°
radius of sector, r = 7 cm
Ans: (1)
Area of an equilateral triangle =
\begin{gathered} \frac{ \sqrt{3} }{4} {a}^{2} \\ = > \frac{ \sqrt{3} }{4} \times {14}^{2} = 49 \sqrt{3} {cm}^{2} \end{gathered}43a2=>43×142=493cm2
Ans: (2)
Area of a sector
\begin{gathered} = \frac{\pi {r}^{2} }{360 \degree} \times \theta = \frac{\pi \times {7}^{2} }{360 \degree} \times 60 \degree \\ = > \frac{49\pi}{6} {cm}^{2} \end{gathered}=360°πr2×θ=360°π×72×60°=>649πcm2
Ans:(3) Since, All sectors are of same measure :
Total Area of Three sectors :
3*Area of one sector
=>
3 \times \frac{49\pi}{6} = \frac{49\pi}{2} {cm}^{2}3×649π=249πcm2
4) Area of Shaded Region
= Area of Triangle - Area of Three sectors
=
(49 \sqrt{3} - \frac{49\pi}{2} ) {cm}^{2}(493−249π)cm2
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