What point defects are possible for mgo as an impurity in al2o3? how many mg2+ ions must be added to form each of these defects?
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is its maths qstion......
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Answer:
Step-by-step explanation:
For every
Mg ion 2+
that substitutes for
3 Al +
in Al2O3
, a single positive charge is
removed. Thus, in order to maintain charge neutrality, either a positive charge must be added or a
negative charge must be removed.
Positive charges are added by forming
3 Al +
interstitials, and one
3 Al +
interstitial would be
formed for every three
Mg ions 2+
added.
Negative charges may be removed by forming
2 O - vacancies, and one oxygen vacancy would be
formed for every two
Mg ions 2+ added.
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