Question

what point on the x axis is equidistant from (7,6) and (-3,4) answer fast pls

Answer 1

Step-by-step explanation:

Let the required point on the x-axis be (x,0)

Given (x,0) is equidistant from (7,6) and (−3,4)

∴Distance between (x,0)≡(x

1

,y

1

) and (7,6)=(x

2

,y

2

)=distance between (x,0)≡(x

1

,y

1

) and (−3,4)≡(x

2

,y

2

)

Distance Formula =

(x

2

−x

1

)

2

+(y

2

−y

1

)

2