Question

what point on the x-axis is equidistant from the points (7, 6) and (-3, 4) ?​

Answer 1

Step-by-step explanation:

I hope it's helpfull and nice

Answer 2

Step-by-step explanation:

let us consider a point on x axis be (a,0)

distance between (7,6) and (a,0)

√((7-a)^2)+(6-0)^2

= √(49+a^2-14a)+36

=√a^2-14a+85

distance between (-3,4) and (a,0)

=√(-3-a)^2+(4-0)^2

=√9+a^2+6a+16

=√a^2+6a+25

as they are equidistant

the put equal both

(√a^2-14a+85)=(√a^2+6a+25)

squaring both sides

a^2-14a+85=a^2+6a+25

20a=60

a=3

so point is (3,0)